1890 Idaho gubernatorial election
The 1890 Idaho gubernatorial election was held on 1 October, 1890, in order to elect the first Governor of Idaho upon Idaho acquiring statehood in July 1890. Incumbent Republican Governor of the Idaho Territory George L. Shoup defeated Democratic nominee Benjamin Wilson.[1]
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General election
On election day, 1 October 1890, Republican nominee George L. Shoup won the election by a margin of 2,314 votes against his opponent Democratic nominee Benjamin Wilson, thereby retaining Republican control over the new office of Governor. Shoup was sworn in as the first Governor of the new state of Idaho on 8 December 1890.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | George L. Shoup | 10,262 | 56.35 | |
| Democratic | Benjamin Wilson | 7,948 | 43.65 | |
| Total votes | 18,210 | 100.00 | ||
| Republican hold | ||||
References
- "George L. Shoup". National Governors Association. Retrieved 12 May 2023.
- "ID Governor". ourcampaigns.com. 26 September 2005. Retrieved 12 May 2023.
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