1896 United States presidential election
The 1896 United States presidential election was the 28th presidential election in the United States. It happened on Tuesday, November 3, 1896. Former Governor William McKinley, the Republican candidate, defeated Democrat William Jennings Bryan. The 1896 campaign happened during an economic depression called the Panic of 1893. The election is considered to mark the change from the "Third Party System" to the "Fourth Party System".[2]
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447 members of the Electoral College 224 electoral votes needed to win | ||||||||||||||||||||||||||||||||
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Turnout | 79.3%[1] ![]() | |||||||||||||||||||||||||||||||
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![]() Presidential election results map. Red denotes those won by McKinley/Hobart, blue denotes states won by Bryan/Sewall and the Democratic/Populist ticket of Bryan/Watson. Numbers indicate the number of electoral votes allotted to each state. | ||||||||||||||||||||||||||||||||
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References
- "Voter Turnout in Presidential Elections". The American Presidency Project. UC Santa Barbara.
- Williams (2010)
Other websites

Wikimedia Commons has media related to United States presidential election, 1896.
- United States presidential election of 1896 at Encyclopædia Britannica
- Presidential Election of 1896: A Resource Guide from the Library of Congress
- 1896 popular vote by counties
- How close was the 1896 election? — Michael Sheppard, Massachusetts Institute of Technology
- McKinley & Hobart campaign handkerchief in the Staten Island Historical Society Online Collections Database
- Election of 1896 in Counting the Votes Archived 2019-09-23 at the Wayback Machine
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