Petersburg, Indiana
Petersburg, Indiana is a city in Indiana in the United States. It is the county seat of Pike County.
City of Petersburg | |
|---|---|
 | |
 Location in Indiana | |
| Coordinates: 38°29′30″N 87°16′49″W | |
| Country | United States |
| State | Indiana |
| County | Pike |
| Township | Washington |
| Area | |
| • Total | 1.47 sq mi (3.81 km2) |
| • Land | 1.47 sq mi (3.81 km2) |
| • Water | 0 sq mi (0 km2) 0% |
| Elevation | 482 ft (147 m) |
| Population (2010) | |
| • Total | 2,383 |
| • Estimate (2012[1]) | 2,373 |
| • Density | 1,621.1/sq mi (625.9/km2) |
| Time zone | UTC-6 (EST) |
| • Summer (DST) | UTC-5 (EDT) |
| ZIP code | 47567 |
| Area code(s) | 812 |
| FIPS code | 18-59364[2] |
| GNIS feature ID | 0449709[3] |
| Website | http://www.petersburg.in.gov/ |
References
- "Population Estimates". United States Census Bureau. Retrieved 2013-06-25.
- "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
- "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
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