Jefferson, Ohio

Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,120 at the 2010 census. It is the county seat of Ashtabula County.[4]

Jefferson, Ohio
Village
Ashtabula County Courthouse
Location of Jefferson, Ohio
Location of Jefferson in Ashtabula County
Coordinates: 41°44′14″N 80°46′19″W
CountryUnited States
StateOhio
CountyAshtabula
Government
 • MayorJudy Maloney
Area
 • Total2.52 sq mi (6.53 km2)
 • Land2.52 sq mi (6.53 km2)
 • Water0 sq mi (0 km2)
Elevation
[1]
958 ft (292 m)
Population
 (2010)
 • Total3,120
 • Estimate 
(2018[2])
2,994
 • Density1,238.1/sq mi (478.0/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
44047
Area code(s)440
FIPS code39-38500[3]
GNIS feature ID1042061
Websitehttp://www.jeffersonohio.us/

References
  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "Population and Housing Unit Estimates". Retrieved June 30, 2019.
  3. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  4. "Find a County". National Association of Counties. Archived from the original on 2011-05-31. Retrieved 2011-06-07.


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