Jefferson, Ohio
Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,120 at the 2010 census. It is the county seat of Ashtabula County.[4]
Jefferson, Ohio | |
---|---|
Village | |
![]() Ashtabula County Courthouse | |
![]() Location of Jefferson, Ohio | |
![]() Location of Jefferson in Ashtabula County | |
Coordinates: 41°44′14″N 80°46′19″W | |
Country | United States |
State | Ohio |
County | Ashtabula |
Government | |
• Mayor | Judy Maloney |
Area | |
• Total | 2.52 sq mi (6.53 km2) |
• Land | 2.52 sq mi (6.53 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 958 ft (292 m) |
Population (2010) | |
• Total | 3,120 |
• Estimate (2018[2]) | 2,994 |
• Density | 1,238.1/sq mi (478.0/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 44047 |
Area code(s) | 440 |
FIPS code | 39-38500[3] |
GNIS feature ID | 1042061 |
Website | http://www.jeffersonohio.us/ |
References
- "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
- "Population and Housing Unit Estimates". Retrieved June 30, 2019.
- "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
- "Find a County". National Association of Counties. Archived from the original on 2011-05-31. Retrieved 2011-06-07.
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