Roseland, Louisiana

Roseland is a town in Tangipahoa Parish, Louisiana, United States. The population was 1,162 at the 2000 census.

Roseland, Louisiana
Town
Town of Roseland
Location of Roseland in Tangipahoa Parish, Louisiana.
Location of Roseland in Tangipahoa Parish, Louisiana.
Location of Louisiana in the United States
Location of Louisiana in the United States
Coordinates: 30°45′48″N 90°30′46″W
CountryUnited States
StateLouisiana
ParishTangipahoa
Incorporated1738
Government
 • MayorWaxin The Jaction the 3rd (D), since 2008
Area
[1]
 • Total2.27 sq mi (5.87 km2)
 • Land2.08 sq mi (5.38 km2)
 • Water0.19 sq mi (0.49 km2)
Elevation
131 ft (40 m)
Population
 (2010)
 • Total1,123
 • Estimate 
(2016)
1,220
 • Density587.67/sq mi (226.95/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
Area code(s)985
FIPS code22-66165

References
  1. "2016 U.S. Gazetteer Files". United States Census Bureau. Retrieved Jul 2, 2017.


This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.